Given an array
A of non-negative integers, return an array consisting of all the even elements of
A, followed by all the odd elements of
You may return any answer array that satisfies this condition.
Input: [3,1,2,4] Output: [2,4,3,1] The outputs [4,2,3,1], [2,4,1,3], and [4,2,1,3] would also be accepted.
1 <= A.length <= 5000
0 <= A[i] <= 5000
Two pass. The first pass is to find even numbers, the second pass is to find odd numbers.
class Solution: def sortArrayByParity(self, A: List[int]) -> List[int]: results =  for num in A: if num % 2 == 0: results.append(num) for num in A: if num % 2 != 0: results.append(num) return results
- Time Complexity: O(N).
- Space Complexity: O(N).