# LeetCode 347. Top K Frequent Elements

## Description

https://leetcode.com/problems/top-k-frequent-elements/

Given a non-empty array of integers, return the k most frequent elements.

Example 1:

```Input: nums = [1,1,1,2,2,3], k = 2
Output: [1,2]
```

Example 2:

```Input: nums = , k = 1
Output: ```

Note:

• You may assume k is always valid, 1 ≤ k ≤ number of unique elements.
• Your algorithm’s time complexity must be better than O(n log n), where n is the array’s size.
• It’s guaranteed that the answer is unique, in other words the set of the top k frequent elements is unique.
• You can return the answer in any order.

## Explanation

Use heap is easy to find top k frequent.

## Python Solution

``````class Solution:
def topKFrequent(self, nums: List[int], k: int) -> List[int]:
count = {}

for num in nums:
count[num] = count.get(num, 0) + 1

heap = []
for key, value in count.items():
heapq.heappush(heap, (-value, key))

results = []

for i in range(k):
count, element = heapq.heappop(heap)
results.append(element)

return results``````
• Time complexity: O(N log(k)).
• Space complexity: O(N).