## Description

https://leetcode.com/problems/delete-node-in-a-linked-list/

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Given linked list — head = [4,5,1,9], which looks like following:

**Example 1:**

Input:head = [4,5,1,9], node = 5Output:[4,1,9]Explanation:You are given the second node with value 5, the linked list should become 4 -> 1 -> 9 after calling your function.

**Example 2:**

Input:head = [4,5,1,9], node = 1Output:[4,5,9]Explanation:You are given the third node with value 1, the linked list should become 4 -> 5 -> 9 after calling your function.

**Note:**

- The linked list will have at least two elements.
- All of the nodes’ values will be unique.
- The given node will not be the tail and it will always be a valid node of the linked list.
- Do not return anything from your function.

## Explanation

Simply make the deleting node to be the next node to make it effect.

## Python Solution

```
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution:
def deleteNode(self, node):
"""
:type node: ListNode
:rtype: void Do not return anything, modify node in-place instead.
"""
node.val = node.next.val
node.next = node.next.next
```

- Time complexity: O(1).
- Space complexity: O(1).

/**

* Definition for singly-linked list.

* public class ListNode {

* int val;

* ListNode next;

* ListNode(int x) { val = x; }

* }

*/

class Solution {

public void deleteNode(ListNode node) {

node.val = node.next.val;

node.next = node.next.next;

}

}