# LeetCode 200. Number of Islands

## Description

https://leetcode.com/problems/number-of-islands/

Given a 2d grid map of `'1'`s (land) and `'0'`s (water), count the number of islands. An island is surrounded by water and is formed by connecting adjacent lands horizontally or vertically. You may assume all four edges of the grid are all surrounded by water.

Example 1:

```Input:
11110
11010
11000
00000

Output: 1
```

Example 2:

```Input:
11000
11000
00100
00011

Output: 3```

## Explanation

if encounter ‘1’, an island found, use dfs to visit all its lands, and mark to “0”. Once the process finished. The next encountered ‘1’ suggests another island found.

## Python Solution

``````class Solution:
def numIslands(self, grid: List[List[str]]) -> int:
count = 0

for i in range(0, len(grid)):
for j in range(0, len(grid)):

if grid[i][j] == '1':
self.island_helper(grid, i, j)
count += 1

return count

def island_helper(self, grid, i, j):
if i < 0 or i > len(grid) - 1:
return

if j < 0 or j > len(grid) -1:
return

if grid[i][j] == '0':
return

grid[i][j] = '0'

self.island_helper(grid, i + 1, j)
self.island_helper(grid, i - 1, j)
self.island_helper(grid, i, j + 1)
self.island_helper(grid, i, j - 1)
``````
• Time complexity: O(N).
• Space complexity: O(N).