# LeetCode 1646. Get Maximum in Generated Array

## Description

https://leetcode.com/problems/get-maximum-in-generated-array/

You are given an integer `n`. An array `nums` of length `n + 1` is generated in the following way:

• `nums = 0`
• `nums = 1`
• `nums[2 * i] = nums[i]` when `2 <= 2 * i <= n`
• `nums[2 * i + 1] = nums[i] + nums[i + 1]` when `2 <= 2 * i + 1 <= n`

Returnthe maximum integer in the array `nums`​​​.

Example 1:

```Input: n = 7
Output: 3
Explanation: According to the given rules:
nums = 0
nums = 1
nums[(1 * 2) = 2] = nums = 1
nums[(1 * 2) + 1 = 3] = nums + nums = 1 + 1 = 2
nums[(2 * 2) = 4] = nums = 1
nums[(2 * 2) + 1 = 5] = nums + nums = 1 + 2 = 3
nums[(3 * 2) = 6] = nums = 2
nums[(3 * 2) + 1 = 7] = nums + nums = 2 + 1 = 3
Hence, nums = [0,1,1,2,1,3,2,3], and the maximum is 3.
```

Example 2:

```Input: n = 2
Output: 1
Explanation: According to the given rules, the maximum between nums, nums, and nums is 1.
```

Example 3:

```Input: n = 3
Output: 2
Explanation: According to the given rules, the maximum between nums, nums, nums, and nums is 2.
```

Constraints:

• `0 <= n <= 100`

## Explanation

Implement as the problem describes and find the max from the list.

## Python Solution

``````class Solution:
def getMaximumGenerated(self, n: int) -> int:
if n < 1:
return 0

nums = [None for i in range(n + 1)]

nums = 0
nums = 1

for i in range(0, n + 1):

if 2 <= 2 * i <= n:
nums[2 * i] = nums[i]

if 2 <= 2 * i + 1 <= n:
nums[2 * i + 1] = nums[i] + nums[i + 1]

return max(nums)
``````
• Time Complexity: O(N).
• Space Complexity: O(N).