# LeetCode 1476. Subrectangle Queries

## Description

https://leetcode.com/problems/subrectangle-queries/

Implement the class `SubrectangleQueries` which receives a `rows x cols` rectangle as a matrix of integers in the constructor and supports two methods:

1.` updateSubrectangle(int row1, int col1, int row2, int col2, int newValue)`

• Updates all values with `newValue` in the subrectangle whose upper left coordinate is `(row1,col1)` and bottom right coordinate is `(row2,col2)`.

2.` getValue(int row, int col)`

• Returns the current value of the coordinate `(row,col)` from the rectangle.

Example 1:

```Input
[[[[1,2,1],[4,3,4],[3,2,1],[1,1,1]]],[0,2],[0,0,3,2,5],[0,2],[3,1],[3,0,3,2,10],[3,1],[0,2]]
Output
```

[null,1,null,5,5,null,10,5]

Explanation SubrectangleQueries subrectangleQueries = new SubrectangleQueries([[1,2,1],[4,3,4],[3,2,1],[1,1,1]]); // The initial rectangle (4×3) looks like: // 1 2 1 // 4 3 4 // 3 2 1 // 1 1 1 subrectangleQueries.getValue(0, 2); // return 1 subrectangleQueries.updateSubrectangle(0, 0, 3, 2, 5); // After this update the rectangle looks like: // 5 5 5 // 5 5 5 // 5 5 5 // 5 5 5 subrectangleQueries.getValue(0, 2); // return 5 subrectangleQueries.getValue(3, 1); // return 5 subrectangleQueries.updateSubrectangle(3, 0, 3, 2, 10); // After this update the rectangle looks like: // 5 5 5 // 5 5 5 // 5 5 5 // 10 10 10 subrectangleQueries.getValue(3, 1); // return 10 subrectangleQueries.getValue(0, 2); // return 5

Example 2:

```Input
[[[[1,1,1],[2,2,2],[3,3,3]]],[0,0],[0,0,2,2,100],[0,0],[2,2],[1,1,2,2,20],[2,2]]
Output
```

[null,1,null,100,100,null,20]

Explanation SubrectangleQueries subrectangleQueries = new SubrectangleQueries([[1,1,1],[2,2,2],[3,3,3]]); subrectangleQueries.getValue(0, 0); // return 1 subrectangleQueries.updateSubrectangle(0, 0, 2, 2, 100); subrectangleQueries.getValue(0, 0); // return 100 subrectangleQueries.getValue(2, 2); // return 100 subrectangleQueries.updateSubrectangle(1, 1, 2, 2, 20); subrectangleQueries.getValue(2, 2); // return 20

Constraints:

• There will be at most `500` operations considering both methods: `updateSubrectangle` and `getValue`.
• `1 <= rows, cols <= 100`
• `rows == rectangle.length`
• `cols == rectangle[i].length`
• `0 <= row1 <= row2 < rows`
• `0 <= col1 <= col2 < cols`
• `1 <= newValue, rectangle[i][j] <= 10^9`
• `0 <= row < rows`
• `0 <= col < cols`

## Explanation

Treat the rectangle as matrix and update values base on given indexes.

## Python Solution

``````class SubrectangleQueries:

def __init__(self, rectangle: List[List[int]]):
self.rectangle = rectangle

def updateSubrectangle(self, row1: int, col1: int, row2: int, col2: int, newValue: int) -> None:
for i in range(row1, row2 + 1):
for j in range(col1, col2 + 1):
self.rectangle[i][j] = newValue

def getValue(self, row: int, col: int) -> int:
return self.rectangle[row][col]

# Your SubrectangleQueries object will be instantiated and called as such:
# obj = SubrectangleQueries(rectangle)