LeetCode 1491. Average Salary Excluding the Minimum and Maximum Salary

Description

https://leetcode.com/problems/average-salary-excluding-the-minimum-and-maximum-salary/

Given an array of unique integers salary where salary[i] is the salary of the employee i.

Return the average salary of employees excluding the minimum and maximum salary.

Example 1:

Input: salary = [4000,3000,1000,2000]
Output: 2500.00000
Explanation: Minimum salary and maximum salary are 1000 and 4000 respectively.
Average salary excluding minimum and maximum salary is (2000+3000)/2= 2500

Example 2:

Input: salary = [1000,2000,3000]
Output: 2000.00000
Explanation: Minimum salary and maximum salary are 1000 and 3000 respectively.
Average salary excluding minimum and maximum salary is (2000)/1= 2000

Example 3:

Input: salary = [6000,5000,4000,3000,2000,1000]
Output: 3500.00000

Example 4:

Input: salary = [8000,9000,2000,3000,6000,1000]
Output: 4750.00000

Constraints:

• 3 <= salary.length <= 100
• 10^3 <= salary[i] <= 10^6
• salary[i] is unique.
• Answers within 10^-5 of the actual value will be accepted as correct.

Explanation

Iterate the list and calculate the average exclude the element with the minimum and maximum value.

Python Solution

class Solution:
    def average(self, salary: List[int]) -> float:
        
        max_salary = max(salary)
        
        min_salary = min(salary)
        
        salary_sum = 0
        count = 0
        for s in salary:
            if s != min_salary and s != max_salary:
                salary_sum += s
                count += 1
                
        
        return salary_sum / count