# LeetCode 1491. Average Salary Excluding the Minimum and Maximum Salary

## Description

https://leetcode.com/problems/average-salary-excluding-the-minimum-and-maximum-salary/

Given an array of unique integers `salary` where `salary[i]` is the salary of the employee `i`.

Return the average salary of employees excluding the minimum and maximum salary.

Example 1:

```Input: salary = [4000,3000,1000,2000]
Output: 2500.00000
Explanation: Minimum salary and maximum salary are 1000 and 4000 respectively.
Average salary excluding minimum and maximum salary is (2000+3000)/2= 2500
```

Example 2:

```Input: salary = [1000,2000,3000]
Output: 2000.00000
Explanation: Minimum salary and maximum salary are 1000 and 3000 respectively.
Average salary excluding minimum and maximum salary is (2000)/1= 2000
```

Example 3:

```Input: salary = [6000,5000,4000,3000,2000,1000]
Output: 3500.00000
```

Example 4:

```Input: salary = [8000,9000,2000,3000,6000,1000]
Output: 4750.00000
```

Constraints:

• `3 <= salary.length <= 100`
• `10^3 <= salary[i] <= 10^6`
• `salary[i]` is unique.
• Answers within `10^-5` of the actual value will be accepted as correct.

## Explanation

Iterate the list and calculate the average exclude the element with the minimum and maximum value.

## Python Solution

``````class Solution:
def average(self, salary: List[int]) -> float:

max_salary = max(salary)

min_salary = min(salary)

salary_sum = 0
count = 0
for s in salary:
if s != min_salary and s != max_salary:
salary_sum += s
count += 1

return salary_sum / count ``````
• Time Complexity: O(N).
• Space Complexity: O(1).