Description
https://leetcode.com/problems/squares-of-a-sorted-array/
Given an integer array nums
sorted in non-decreasing order, return an array of the squares of each number sorted in non-decreasing order.
Example 1:
Input: nums = [-4,-1,0,3,10] Output: [0,1,9,16,100] Explanation: After squaring, the array becomes [16,1,0,9,100]. After sorting, it becomes [0,1,9,16,100].
Example 2:
Input: nums = [-7,-3,2,3,11] Output: [4,9,9,49,121]
Constraints:
1 <= nums.length <= 104
-104 <= nums[i] <= 104
nums
is sorted in non-decreasing order.
Follow up: Squaring each element and sorting the new array is very trivial, could you find an O(n)
solution using a different approach?
Explanation
Find squares of nums and then sorted the squared nums.
Python Solution
class Solution:
def sortedSquares(self, nums: List[int]) -> List[int]:
squared_nums = [num**2 for num in nums]
return list(sorted(squared_nums))
- Time Complexity: O(Nlog(N))
- Space Complexity: O(N)