Description
https://leetcode.com/problems/jewels-and-stones/
You’re given strings J
representing the types of stones that are jewels, and S
representing the stones you have. Each character in S
is a type of stone you have. You want to know how many of the stones you have are also jewels.
The letters in J
are guaranteed distinct, and all characters in J
and S
are letters. Letters are case sensitive, so "a"
is considered a different type of stone from "A"
.
Example 1:
Input: J = "aA", S = "aAAbbbb" Output: 3
Example 2:
Input: J = "z", S = "ZZ" Output: 0
Note:
S
andJ
will consist of letters and have length at most 50.- The characters in
J
are distinct.
Explanation
Simply count how many stones in jewels.
Python Solution
class Solution:
def numJewelsInStones(self, J: str, S: str) -> int:
J = set(J)
count = 0
for c in S:
if c in J:
count += 1
return count
- Time Complexity: O(J.length + S.length)
- Space Complexity: O(J.length)