Description
https://leetcode.com/problems/toeplitz-matrix/
Given an m x n matrix, return true if the matrix is Toeplitz. Otherwise, return false.
A matrix is Toeplitz if every diagonal from top-left to bottom-right has the same elements.
Example 1:

Input: matrix = [[1,2,3,4],[5,1,2,3],[9,5,1,2]] Output: true Explanation: In the above grid, the diagonals are: "[9]", "[5, 5]", "[1, 1, 1]", "[2, 2, 2]", "[3, 3]", "[4]". In each diagonal all elements are the same, so the answer is True.
Example 2:

Input: matrix = [[1,2],[2,2]] Output: false Explanation: The diagonal "[1, 2]" has different elements.
Constraints:
m == matrix.lengthn == matrix[i].length1 <= m, n <= 200 <= matrix[i][j] <= 99
Follow up:
- What if the
matrixis stored on disk, and the memory is limited such that you can only load at most one row of the matrix into the memory at once? - What if the
matrixis so large that you can only load up a partial row into the memory at once?
Explanation
Compare each element with its top-left neighbor to see if the values are the same.
Python Solution
class Solution:
def isToeplitzMatrix(self, matrix: List[List[int]]) -> bool:
if not matrix:
return False
for i in range(1, len(matrix)):
for j in range(1, len(matrix[0])):
if matrix[i][j] != matrix[i - 1][j - 1]:
return False
return True
- Time Complexity: O(MN)
- Space Complexity: O(1)