Description
https://leetcode.com/problems/prime-number-of-set-bits-in-binary-representation/
Given two integers left and right, find the count of numbers in the range [left, right] (inclusive) having a prime number of set bits in their binary representation.
(Recall that the number of set bits an integer has is the number of 1s present when written in binary. For example, 21 written in binary is 10101 which has 3 set bits. Also, 1 is not a prime.)
Example 1:
Input: left = 6, right = 10 Output: 4 Explanation: 6 -> 110 (2 set bits, 2 is prime) 7 -> 111 (3 set bits, 3 is prime) 9 -> 1001 (2 set bits , 2 is prime) 10->1010 (2 set bits , 2 is prime)
Example 2:
Input: left = 10, right = 15 Output: 5 Explanation: 10 -> 1010 (2 set bits, 2 is prime) 11 -> 1011 (3 set bits, 3 is prime) 12 -> 1100 (2 set bits, 2 is prime) 13 -> 1101 (3 set bits, 3 is prime) 14 -> 1110 (3 set bits, 3 is prime) 15 -> 1111 (4 set bits, 4 is not prime)
Note:
left, rightwill be integersleft <= rightin the range[1, 10^6].right - leftwill be at most 10000.
Explanation
Convert integer to bits and count how many bits are there. And then check if the count of bits is a prime number
Python Solution
class Solution:
def countPrimeSetBits(self, L: int, R: int) -> int:
count = 0
for i in range(L, R + 1):
bin_i = bin(i)[2:]
count_bits = bin_i.count('1')
if count_bits > 1 and self.is_prime(count_bits):
count += 1
return count
def is_prime(self, n):
for i in range(2, floor(sqrt(n)) + 1):
if n % i == 0:
return False
return True
- Time Complexity: O(N^2).
- Space Complexity: O(N).