Description
https://leetcode.com/problems/find-anagram-mappings/
Given two lists A
and B
, and B
is an anagram of A
. B
is an anagram of A
means B
is made by randomizing the order of the elements in A
.
We want to find an index mapping P
, from A
to B
. A mapping P[i] = j
means the i
th element in A
appears in B
at index j
.
These lists A
and B
may contain duplicates. If there are multiple answers, output any of them.
For example, given
A = [12, 28, 46, 32, 50] B = [50, 12, 32, 46, 28]
We should return
[1, 4, 3, 2, 0]
as P[0] = 1
because the 0
th element of A
appears at B[1]
, and P[1] = 4
because the 1
st element of A
appears at B[4]
, and so on.
Note:
A, B
have equal lengths in range[1, 100]
.A[i], B[i]
are integers in range[0, 10^5]
.
Explanation
Find A’s numbers’ indices in B.
Python Solution
class Solution:
def anagramMappings(self, A: List[int], B: List[int]) -> List[int]:
results = []
for number in A:
results.append(B.index(number))
return results
- Time Complexity: O(N)
- Space Complexity: O(N)