LeetCode 412. Fizz Buzz

Description

https://leetcode.com/problems/fizz-buzz/

Write a program that outputs the string representation of numbers from 1 to n.

But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.

Example:

n = 15,

Return:
[
    "1",
    "2",
    "Fizz",
    "4",
    "Buzz",
    "Fizz",
    "7",
    "8",
    "Fizz",
    "Buzz",
    "11",
    "Fizz",
    "13",
    "14",
    "FizzBuzz"
]

Explanation

Just iterate numbers from 1 to n.

• If (number % 3 == 0 and number % 5 == 0), output “FizzBuzz”.
• If (number % 3 == 0), output “Fizz”.
• If (number % 5 == 0), output “Buzz”.
• For all other cases, just output the string value of the number.

Java Solution

class Solution {
  public List<String> fizzBuzz(int n) {
    List<String> result = new ArrayList<>();

    for (int i = 1; i <= n; i++) {
      if (i % 3 == 0 && i % 5 == 0) {
        result.add("FizzBuzz");
      } else if (i % 3 == 0) {
        result.add("Fizz");
      } else if (i % 5 == 0) {
        result.add("Buzz");
      } else {
        result.add(Integer.toString(i));
      }
    }

    return result;
  }
}

Python Solution

class Solution:
    def fizzBuzz(self, n: int) -> List[str]:
        result = []
        
        for i in range(1, n + 1):
            if i % 3 == 0 and i % 5 == 0: 
                result.append("FizzBuzz")

            elif i % 3 == 0: 
                result.append("Fizz")

            elif i % 5 == 0: 
                result.append("Buzz")

            else: 
                result.append(str(i))        

        return result

• Time Complexity: O(N)
• Space Complexity: O(1)