LeetCode 359. Logger Rate Limiter

Description

https://leetcode.com/problems/logger-rate-limiter/

Design a logger system that receives a stream of messages along with their timestamps. Each unique message should only be printed at most every 10 seconds (i.e. a message printed at timestamp t will prevent other identical messages from being printed until timestamp t + 10).

All messages will come in chronological order. Several messages may arrive at the same timestamp.

Implement the Logger class:

• Logger() Initializes the logger object.
• bool shouldPrintMessage(int timestamp, string message) Returns true if the message should be printed in the given timestamp, otherwise returns false.

Example 1:

Input
["Logger", "shouldPrintMessage", "shouldPrintMessage", "shouldPrintMessage", "shouldPrintMessage", "shouldPrintMessage", "shouldPrintMessage"]
[[], [1, "foo"], [2, "bar"], [3, "foo"], [8, "bar"], [10, "foo"], [11, "foo"]]
Output

[null, true, true, false, false, false, true]

Explanation Logger logger = new Logger(); logger.shouldPrintMessage(1, “foo”); // return true, next allowed timestamp for “foo” is 1 + 10 = 11 logger.shouldPrintMessage(2, “bar”); // return true, next allowed timestamp for “bar” is 2 + 10 = 12 logger.shouldPrintMessage(3, “foo”); // 3 < 11, return false logger.shouldPrintMessage(8, “bar”); // 8 < 12, return false logger.shouldPrintMessage(10, “foo”); // 10 < 11, return false logger.shouldPrintMessage(11, “foo”); // 11 >= 11, return true, next allowed timestamp for “foo” is 11 + 10 = 21

Constraints:

• 0 <= timestamp <= 109
• Every timestamp will be passed in non-decreasing order (chronological order).
• 1 <= message.length <= 30
• At most 104 calls will be made to shouldPrintMessage.

Python Solution

Use a hashmap to track the last updated time of the message.

class Logger:

    def __init__(self):
        self.logger = {}

    def shouldPrintMessage(self, timestamp: int, message: str) -> bool:
        
        if message not in self.logger:
            self.logger[message] = timestamp
            return True
        
        if timestamp - self.logger[message] < 10:
            return False
        
        self.logger[message] = timestamp
        
        return True
    

# Your Logger object will be instantiated and called as such:
# obj = Logger()
# param_1 = obj.shouldPrintMessage(timestamp,message)

• Time Complexity: ~N
• Space Complexity: ~N