Description
https://leetcode.com/problems/missing-number/
Given an array containing n distinct numbers taken from 0, 1, 2, ..., n
, find the one that is missing from the array.
Example 1:
Input: [3,0,1] Output: 2
Example 2:
Input: [9,6,4,2,3,5,7,0,1] Output: 8
Note:
Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity?
Explanation
use a hashmap to help check which number is missing
Python Solution
class Solution:
def missingNumber(self, nums: List[int]) -> int:
n = len(nums)
visited = set()
for num in nums:
visited.add(num)
for i in range(0, n + 1):
if i not in visited:
return i
- Time complexity: O(N).
- Space complexity: O(1).
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