Description
https://leetcode.com/problems/convert-binary-number-in-a-linked-list-to-integer/
Given head
which is a reference node to a singly-linked list. The value of each node in the linked list is either 0 or 1. The linked list holds the binary representation of a number.
Return the decimal value of the number in the linked list.
Example 1:
Input: head = [1,0,1] Output: 5 Explanation: (101) in base 2 = (5) in base 10
Example 2:
Input: head = [0] Output: 0
Example 3:
Input: head = [1] Output: 1
Example 4:
Input: head = [1,0,0,1,0,0,1,1,1,0,0,0,0,0,0] Output: 18880
Example 5:
Input: head = [0,0] Output: 0
Constraints:
- The Linked List is not empty.
- Number of nodes will not exceed
30
. - Each node’s value is either
0
or1
.
Explanation
Multiply result by 2.
Python Solution
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution:
def getDecimalValue(self, head: ListNode) -> int:
result = 0
while head:
result = result * 2 + head.val
head = head.next
return result
- Time Complexity: O(N)
- Space Complexity: O(1)