Description
https://leetcode.com/problems/employees-earning-more-than-their-managers/
The Employee
table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id.
+----+-------+--------+-----------+ | Id | Name | Salary | ManagerId | +----+-------+--------+-----------+ | 1 | Joe | 70000 | 3 | | 2 | Henry | 80000 | 4 | | 3 | Sam | 60000 | NULL | | 4 | Max | 90000 | NULL | +----+-------+--------+-----------+
Given the Employee
table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager.
+----------+ | Employee | +----------+ | Joe | +----------+
Explanation
select the same table twice. The first select is to get employee salary, the second select is to get manager’s salary.
SQL Solution
# Write your MySQL query statement below
select Name as Employee from Employee e where e.Salary > (SELECT Salary FROM Employee m WHERE m.Id = e.ManagerId)
I found this solution very popular and helpful: https://www.youtube.com/watch?v=qTC1yikW4Gg&ab_channel=EricProgramming